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1140211323 = 3414076683
BaseRepresentation
bin100001111110110…
…0011111001111011
32221110111201220000
41003331203321323
54313343230243
6305050404043
740153431156
oct10375437173
92843451800
101140211323
1153568a709
12279a30623
131522bc774
14ab608c9d
156a17a5d3
hex43f63e7b

1140211323 has 10 divisors (see below), whose sum is σ = 1703278764. Its totient is φ = 760140828.

The previous prime is 1140211297. The next prime is 1140211327. The reversal of 1140211323 is 3231120411.

It is not a de Polignac number, because 1140211323 - 25 = 1140211291 is a prime.

It is a super-2 number, since 2×11402113232 = 2600163722194820658, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1140211296 and 1140211305.

It is not an unprimeable number, because it can be changed into a prime (1140211327) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 7038261 + ... + 7038422.

Almost surely, 21140211323 is an apocalyptic number.

1140211323 is a deficient number, since it is larger than the sum of its proper divisors (563067441).

1140211323 is an equidigital number, since it uses as much as digits as its factorization.

1140211323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14076695 (or 14076686 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 1140211323 is about 33767.0153108029. The cubic root of 1140211323 is about 1044.7084717490.

Adding to 1140211323 its reverse (3231120411), we get a palindrome (4371331734).

The spelling of 1140211323 in words is "one billion, one hundred forty million, two hundred eleven thousand, three hundred twenty-three".

Divisors: 1 3 9 27 81 14076683 42230049 126690147 380070441 1140211323