Base | Representation |
---|---|
bin | 110101000110011001… |
… | …0111011111000111001 |
3 | 101220100001000212102021 |
4 | 1222030302323320321 |
5 | 3332014003444231 |
6 | 124215114434441 |
7 | 11144542106644 |
oct | 1521462737071 |
9 | 356301025367 |
10 | 114031312441 |
11 | 443a6780892 |
12 | 1a124a32a21 |
13 | a9a3762a97 |
14 | 573a768a5b |
15 | 2e75ea5811 |
hex | 1a8ccbbe39 |
114031312441 has 16 divisors (see below), whose sum is σ = 119209584384. Its totient is φ = 108979363584.
The previous prime is 114031312411. The next prime is 114031312453. The reversal of 114031312441 is 144213130411.
It is a cyclic number.
It is not a de Polignac number, because 114031312441 - 215 = 114031279673 is a prime.
It is a super-2 number, since 2×1140313124412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114031312411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 768225 + ... + 904561.
It is an arithmetic number, because the mean of its divisors is an integer number (7450599024).
Almost surely, 2114031312441 is an apocalyptic number.
It is an amenable number.
114031312441 is a deficient number, since it is larger than the sum of its proper divisors (5178271943).
114031312441 is a wasteful number, since it uses less digits than its factorization.
114031312441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 136800.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 114031312441 its reverse (144213130411), we get a palindrome (258244442852).
The spelling of 114031312441 in words is "one hundred fourteen billion, thirty-one million, three hundred twelve thousand, four hundred forty-one".
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