Base | Representation |
---|---|
bin | 11001111100100010011101… |
… | …100001110101110000110011 |
3 | 112222000221022001211101121100 |
4 | 121330202131201311300303 |
5 | 104424100003001422003 |
6 | 1042410005000055443 |
7 | 33015162143161044 |
oct | 3174423541656063 |
9 | 488027261741540 |
10 | 114111334014003 |
11 | 333a53881a1387 |
12 | 1096b65aa64583 |
13 | 4b89863a80a91 |
14 | 20270376ba8cb |
15 | d2d46e973ba3 |
hex | 67c89d875c33 |
114111334014003 has 48 divisors (see below), whose sum is σ = 169397344771200. Its totient is φ = 73992819479040.
The previous prime is 114111334013983. The next prime is 114111334014037. The reversal of 114111334014003 is 300410433111411.
114111334014003 is a `hidden beast` number, since 1 + 141 + 113 + 3 + 4 + 0 + 1 + 400 + 3 = 666.
It is not a de Polignac number, because 114111334014003 - 210 = 114111334012979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (114111334014203) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 181970268 + ... + 182596278.
It is an arithmetic number, because the mean of its divisors is an integer number (3529111349400).
Almost surely, 2114111334014003 is an apocalyptic number.
114111334014003 is a deficient number, since it is larger than the sum of its proper divisors (55286010757197).
114111334014003 is a wasteful number, since it uses less digits than its factorization.
114111334014003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 629712 (or 629709 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 114111334014003 its reverse (300410433111411), we get a palindrome (414521767125414).
The spelling of 114111334014003 in words is "one hundred fourteen trillion, one hundred eleven billion, three hundred thirty-four million, fourteen thousand, three".
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