11411324255433 has 16 divisors (see below), whose sum is σ = 15292100044800. Its totient is φ = 7569051701904.

The previous prime is 11411324255431. The next prime is 11411324255437. The reversal of 11411324255433 is 33455242311411.

It is not a de Polignac number, because 11411324255433 - 2¹ = 11411324255431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11411324255391 and 11411324255400.

It is not an unprimeable number, because it can be changed into a prime (11411324255431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17240710 + ... + 17890352.

It is an arithmetic number, because the mean of its divisors is an integer number (955756252800).

Almost surely, 2^{11411324255433} is an apocalyptic number.

It is an amenable number.

11411324255433 is a deficient number, since it is larger than the sum of its proper divisors (3880775789367).

11411324255433 is a wasteful number, since it uses less digits than its factorization.

11411324255433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 679268.

The product of its digits is 172800, while the sum is 39.

Adding to 11411324255433 its reverse (33455242311411), we get a palindrome (44866566566844).

The spelling of 11411324255433 in words is "eleven trillion, four hundred eleven billion, three hundred twenty-four million, two hundred fifty-five thousand, four hundred thirty-three".