Base | Representation |
---|---|
bin | 1010011000010100110111… |
… | …0111001011010101011011 |
3 | 1111102002000222202221220001 |
4 | 2212011031313023111123 |
5 | 2443442343302243301 |
6 | 40135024200313431 |
7 | 2255364426610504 |
oct | 246051567132533 |
9 | 44362028687801 |
10 | 11413034415451 |
11 | 3700271432589 |
12 | 1343b0a172877 |
13 | 64a3242c3a56 |
14 | 2b65728a1bab |
15 | 14bd2c551c01 |
hex | a614ddcb55b |
11413034415451 has 16 divisors (see below), whose sum is σ = 11566388584960. Its totient is φ = 11259905735520.
The previous prime is 11413034415443. The next prime is 11413034415457. The reversal of 11413034415451 is 15451443031411.
It is a cyclic number.
It is not a de Polignac number, because 11413034415451 - 23 = 11413034415443 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11413034415451.
It is not an unprimeable number, because it can be changed into a prime (11413034415457) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 783693496 + ... + 783708058.
It is an arithmetic number, because the mean of its divisors is an integer number (722899286560).
Almost surely, 211413034415451 is an apocalyptic number.
11413034415451 is a deficient number, since it is larger than the sum of its proper divisors (153354169509).
11413034415451 is a wasteful number, since it uses less digits than its factorization.
11413034415451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21586.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 11413034415451 its reverse (15451443031411), we get a palindrome (26864477446862).
The spelling of 11413034415451 in words is "eleven trillion, four hundred thirteen billion, thirty-four million, four hundred fifteen thousand, four hundred fifty-one".
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