Base | Representation |
---|---|
bin | 10000101000111010010… |
… | …110100110010101001001 |
3 | 11001022102022122211022220 |
4 | 100220322112212111021 |
5 | 122213231204202213 |
6 | 2233142250004253 |
7 | 145416342133341 |
oct | 20507226462511 |
9 | 4038368584286 |
10 | 1143440303433 |
11 | 400a26272a0a |
12 | 165733a16689 |
13 | 83a9782532c |
14 | 3d4b2933d21 |
15 | 1eb24501e23 |
hex | 10a3a5a6549 |
1143440303433 has 16 divisors (see below), whose sum is σ = 1526316929280. Its totient is φ = 761428832384.
The previous prime is 1143440303431. The next prime is 1143440303441. The reversal of 1143440303433 is 3343030443411.
It is a cyclic number.
It is not a de Polignac number, because 1143440303433 - 21 = 1143440303431 is a prime.
It is a super-2 number, since 2×11434403034332 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1143440303394 and 1143440303403.
It is not an unprimeable number, because it can be changed into a prime (1143440303431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24042085 + ... + 24089597.
It is an arithmetic number, because the mean of its divisors is an integer number (95394808080).
Almost surely, 21143440303433 is an apocalyptic number.
It is an amenable number.
1143440303433 is a deficient number, since it is larger than the sum of its proper divisors (382876625847).
1143440303433 is a wasteful number, since it uses less digits than its factorization.
1143440303433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56448.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 1143440303433 its reverse (3343030443411), we get a palindrome (4486470746844).
The spelling of 1143440303433 in words is "one trillion, one hundred forty-three billion, four hundred forty million, three hundred three thousand, four hundred thirty-three".
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