Base | Representation |
---|---|
bin | 1010011110010001111100… |
… | …1111000001110111000011 |
3 | 1111202212002020111212112202 |
4 | 2213210133033001313003 |
5 | 3002131344311312201 |
6 | 40254023054543415 |
7 | 2265645434340140 |
oct | 247443717016703 |
9 | 44685066455482 |
10 | 11515331354051 |
11 | 373a696388648 |
12 | 135b8b9207b6b |
13 | 656b77946055 |
14 | 2bb4b89d53c7 |
15 | 14e818255c6b |
hex | a791f3c1dc3 |
11515331354051 has 16 divisors (see below), whose sum is σ = 13619252183040. Its totient is φ = 9526382265120.
The previous prime is 11515331354011. The next prime is 11515331354113. The reversal of 11515331354051 is 15045313351511.
It is a de Polignac number, because none of the positive numbers 2k-11515331354051 is a prime.
It is a super-2 number, since 2×115153313540512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11515331353996 and 11515331354014.
It is not an unprimeable number, because it can be changed into a prime (11515331354011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10010135 + ... + 11101056.
It is an arithmetic number, because the mean of its divisors is an integer number (851203261440).
Almost surely, 211515331354051 is an apocalyptic number.
11515331354051 is a deficient number, since it is larger than the sum of its proper divisors (2103920828989).
11515331354051 is a wasteful number, since it uses less digits than its factorization.
11515331354051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21113914.
The product of its (nonzero) digits is 67500, while the sum is 38.
The spelling of 11515331354051 in words is "eleven trillion, five hundred fifteen billion, three hundred thirty-one million, three hundred fifty-four thousand, fifty-one".
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