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115243251421403 = 7193897132223407
BaseRepresentation
bin11010001101000000101001…
…000100000101000011011011
3120010001010222100010110012002
4122031000221010011003123
5110101121134330441103
61045034004022311215
733163023126324350
oct3215005104050333
9503033870113162
10115243251421403
11337a1430050a16
1210b12ab788850b
134c3c51323b021
142065b35b08627
15d4cb1c549488
hex68d0291050db

115243251421403 has 16 divisors (see below), whose sum is σ = 138638916049920. Its totient is φ = 93580703899776.

The previous prime is 115243251421351. The next prime is 115243251421433. The reversal of 115243251421403 is 304124152342511.

It is a cyclic number.

It is not a de Polignac number, because 115243251421403 - 210 = 115243251420379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115243251421433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50720126 + ... + 52943532.

It is an arithmetic number, because the mean of its divisors is an integer number (8664932253120).

Almost surely, 2115243251421403 is an apocalyptic number.

115243251421403 is a deficient number, since it is larger than the sum of its proper divisors (23395664628517).

115243251421403 is a wasteful number, since it uses less digits than its factorization.

115243251421403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2613146.

The product of its (nonzero) digits is 115200, while the sum is 38.

The spelling of 115243251421403 in words is "one hundred fifteen trillion, two hundred forty-three billion, two hundred fifty-one million, four hundred twenty-one thousand, four hundred three".

Divisors: 1 7 19 133 389713 2223407 2727991 7404547 15563849 42244733 51831829 295713131 866490612191 6065434285337 16463321631629 115243251421403