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115477750421403 = 3411447648820663
BaseRepresentation
bin11010010000011011000010…
…010010110001011110011011
3120010212120020222100220211020
4122100123002102301132123
5110113441413101441103
61045333425101533523
733215664210044316
oct3220330222613633
9503776228326736
10115477750421403
1133881925683467
1210b50440b742a3
134c58674a38866
14207321d95d97d
15d53c94589753
hex6906c24b179b

115477750421403 has 16 divisors (see below), whose sum is σ = 157834710007296. Its totient is φ = 75055574180160.

The previous prime is 115477750421351. The next prime is 115477750421413. The reversal of 115477750421403 is 304124057774511.

It is not a de Polignac number, because 115477750421403 - 220 = 115477749372827 is a prime.

It is a super-2 number, since 2×1154777504214032 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (115477750421413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324232351 + ... + 324588312.

It is an arithmetic number, because the mean of its divisors is an integer number (9864669375456).

Almost surely, 2115477750421403 is an apocalyptic number.

115477750421403 is a deficient number, since it is larger than the sum of its proper divisors (42356959585893).

115477750421403 is a wasteful number, since it uses less digits than its factorization.

115477750421403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 648822154.

The product of its (nonzero) digits is 3292800, while the sum is 51.

The spelling of 115477750421403 in words is "one hundred fifteen trillion, four hundred seventy-seven billion, seven hundred fifty million, four hundred twenty-one thousand, four hundred three".

Divisors: 1 3 41 123 1447 4341 59327 177981 648820663 1946461989 26601647183 79804941549 938843499361 2816530498083 38492583473801 115477750421403