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11552012214001 = 727747059126601
BaseRepresentation
bin1010100000011010100110…
…0101011001111011110001
31111220100202121000121212021
42220012221211121323301
53003232010111322001
640322530545031441
72301414426450610
oct250065145317361
944810677017767
1011552012214001
1137541a9809636
121366a35625581
1365a4721743cc
142bd198443877
15150763658ba1
hexa81a9959ef1

11552012214001 has 16 divisors (see below), whose sum is σ = 13250347626880. Its totient is φ = 9865690876800.

The previous prime is 11552012213969. The next prime is 11552012214023. The reversal of 11552012214001 is 10041221025511.

11552012214001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 11552012214001 - 25 = 11552012213969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11552012214901) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91184101 + ... + 91310701.

It is an arithmetic number, because the mean of its divisors is an integer number (828146726680).

Almost surely, 211552012214001 is an apocalyptic number.

It is an amenable number.

11552012214001 is a deficient number, since it is larger than the sum of its proper divisors (1698335412879).

11552012214001 is a wasteful number, since it uses less digits than its factorization.

11552012214001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173944.

The product of its (nonzero) digits is 800, while the sum is 25.

Adding to 11552012214001 its reverse (10041221025511), we get a palindrome (21593233239512).

The spelling of 11552012214001 in words is "eleven trillion, five hundred fifty-two billion, twelve million, two hundred fourteen thousand, one".

Divisors: 1 7 277 1939 47059 126601 329413 886207 13035343 35068477 91247401 245479339 5957716459 41704015213 1650287459143 11552012214001