11937432693481 has 3 divisors (see below), whose sum is σ = 11937436148541. Its totient is φ = 11937429238422.

The previous prime is 11937432693479. The next prime is 11937432693521. The reversal of 11937432693481 is 18439623473911.

The square root of 11937432693481 is 3455059.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is not a de Polignac number, because 11937432693481 - 2¹ = 11937432693479 is a prime.

It is a super-3 number, since 3×11937432693481³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11937432693881) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 1727530 + ... + 5182588.

It is an arithmetic number, because the mean of its divisors is an integer number (3979145382847).

Almost surely, 2^{11937432693481} is an apocalyptic number.

11937432693481 is the 3455059-th square number.

11937432693481 is the 1727530-th centered octagonal number.

It is an amenable number.

11937432693481 is a deficient number, since it is larger than the sum of its proper divisors (3455060).

11937432693481 is an frugal number, since it uses more digits than its factorization.

11937432693481 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6910118 (or 3455059 counting only the distinct ones).

The product of its digits is 23514624, while the sum is 61.

The spelling of 11937432693481 in words is "eleven trillion, nine hundred thirty-seven billion, four hundred thirty-two million, six hundred ninety-three thousand, four hundred eighty-one".