11974513497241 has 3 divisors (see below), whose sum is σ = 11974516957663. Its totient is φ = 11974510036820.

The previous prime is 11974513497229. The next prime is 11974513497259. The reversal of 11974513497241 is 14279431547911.

The square root of 11974513497241 is 3460421.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in only one way, i.e., 5734209733641 + 6240303763600 = 2394621^2 + 2498060^2 .

It is a de Polignac number, because none of the positive numbers 2^k-11974513497241 is a prime.

It is a super-2 number, since 2×11974513497241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11974513497211) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 1730211 + ... + 5190631.

Almost surely, 2^{11974513497241} is an apocalyptic number.

11974513497241 is the 3460421-st square number.

11974513497241 is the 1730211-st centered octagonal number.

It is an amenable number.

11974513497241 is a deficient number, since it is larger than the sum of its proper divisors (3460422).

11974513497241 is an frugal number, since it uses more digits than its factorization.

11974513497241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6920842 (or 3460421 counting only the distinct ones).

The product of its digits is 7620480, while the sum is 58.

The spelling of 11974513497241 in words is "eleven trillion, nine hundred seventy-four billion, five hundred thirteen million, four hundred ninety-seven thousand, two hundred forty-one".