Base | Representation |
---|---|
bin | 1010111010100100011010… |
… | …0010010011000010101001 |
3 | 1120111022111202200201201102 |
4 | 2232221012202103002221 |
5 | 3033112201414133113 |
6 | 41305155313331145 |
7 | 2346031643010152 |
oct | 256510642230251 |
9 | 46438452621642 |
10 | 12001322021033 |
11 | 3907806452874 |
12 | 1419b2a566ab5 |
13 | 690948567b57 |
14 | 2d6c1d3d2929 |
15 | 15c2ae010758 |
hex | aea468930a9 |
12001322021033 has 16 divisors (see below), whose sum is σ = 12291791468880. Its totient is φ = 11714272690176.
The previous prime is 12001322021009. The next prime is 12001322021047. The reversal of 12001322021033 is 33012022310021.
It can be written as a sum of positive squares in 8 ways, for example, as 1598942547049 + 10402379473984 = 1264493^2 + 3225272^2 .
It is a cyclic number.
It is not a de Polignac number, because 12001322021033 - 26 = 12001322020969 is a prime.
It is a super-2 number, since 2×120013220210332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12001322020996 and 12001322021014.
It is not an unprimeable number, because it can be changed into a prime (12001322021083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 193485641 + ... + 193547657.
It is an arithmetic number, because the mean of its divisors is an integer number (768236966805).
Almost surely, 212001322021033 is an apocalyptic number.
It is an amenable number.
12001322021033 is a deficient number, since it is larger than the sum of its proper divisors (290469447847).
12001322021033 is an equidigital number, since it uses as much as digits as its factorization.
12001322021033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89516.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 12001322021033 its reverse (33012022310021), we get a palindrome (45013344331054).
The spelling of 12001322021033 in words is "twelve trillion, one billion, three hundred twenty-two million, twenty-one thousand, thirty-three".
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