Base | Representation |
---|---|
bin | 11011010011111111101000… |
… | …000101110010110011000011 |
3 | 120202022110221001010120011020 |
4 | 123103333220011302303003 |
5 | 111221031302003401011 |
6 | 1103250534320520523 |
7 | 34205321260655166 |
oct | 3323775005626303 |
9 | 522273831116136 |
10 | 120121244200131 |
11 | 353021518842a9 |
12 | 11580375780143 |
13 | 5204500312a25 |
14 | 2193c8372dadd |
15 | dd4968978006 |
hex | 6d3fe8172cc3 |
120121244200131 has 32 divisors (see below), whose sum is σ = 162526713850368. Its totient is φ = 78899829953280.
The previous prime is 120121244200079. The next prime is 120121244200141. The reversal of 120121244200131 is 131002442121021.
It is not a de Polignac number, because 120121244200131 - 210 = 120121244199107 is a prime.
It is a super-2 number, since 2×1201212442001312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120121244200141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6186385935 + ... + 6186405351.
It is an arithmetic number, because the mean of its divisors is an integer number (5078959807824).
Almost surely, 2120121244200131 is an apocalyptic number.
120121244200131 is a deficient number, since it is larger than the sum of its proper divisors (42405469650237).
120121244200131 is a wasteful number, since it uses less digits than its factorization.
120121244200131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37531.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 120121244200131 its reverse (131002442121021), we get a palindrome (251123686321152).
The spelling of 120121244200131 in words is "one hundred twenty trillion, one hundred twenty-one billion, two hundred forty-four million, two hundred thousand, one hundred thirty-one".
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