Search a number
-
+
120131011201002 = 23108591843801013
BaseRepresentation
bin11011010100001000101110…
…001111111100011111101010
3120202100102010201110121120020
4123110020232033330133222
5111221211302331413002
61103255231421341310
734206115306053324
oct3324105617743752
9522312121417506
10120131011201002
113530630401764a
1211582240707836
1352053c8960a99
14219452c960614
15dd4d3b15e2bc
hex6d422e3fc7ea

120131011201002 has 16 divisors (see below), whose sum is σ = 240284148144480. Its totient is φ = 40039982776592.

The previous prime is 120131011200961. The next prime is 120131011201009. The reversal of 120131011201002 is 200102110131021.

It is a super-3 number, since 3×1201310112010023 (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (120131011201009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 921835353 + ... + 921965660.

It is an arithmetic number, because the mean of its divisors is an integer number (15017759259030).

Almost surely, 2120131011201002 is an apocalyptic number.

120131011201002 is an abundant number, since it is smaller than the sum of its proper divisors (120153136943478).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131011201002 is a wasteful number, since it uses less digits than its factorization.

120131011201002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1843811877.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 120131011201002 its reverse (200102110131021), we get a palindrome (320233121332023).

The spelling of 120131011201002 in words is "one hundred twenty trillion, one hundred thirty-one billion, eleven million, two hundred one thousand, two".

Divisors: 1 2 3 6 10859 21718 32577 65154 1843801013 3687602026 5531403039 11062806078 20021835200167 40043670400334 60065505600501 120131011201002