Base | Representation |
---|---|
bin | 1010111011010001011111… |
… | …0101011100000010100010 |
3 | 1120112110202010121001110020 |
4 | 2232310113311130002202 |
5 | 3033311442343130422 |
6 | 41314520204214310 |
7 | 2346640555066422 |
oct | 256642765340242 |
9 | 46473663531406 |
10 | 12013423411362 |
11 | 39119563654aa |
12 | 142034723a396 |
13 | 691b2670bc49 |
14 | 2d764a684482 |
15 | 15c76b60c95c |
hex | aed17d5c0a2 |
12013423411362 has 32 divisors (see below), whose sum is σ = 24676458181632. Its totient is φ = 3896207990784.
The previous prime is 12013423411361. The next prime is 12013423411411. The reversal of 12013423411362 is 26311432431021.
12013423411362 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (12013423411361) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31751743 + ... + 32127869.
It is an arithmetic number, because the mean of its divisors is an integer number (771139318176).
Almost surely, 212013423411362 is an apocalyptic number.
12013423411362 is an abundant number, since it is smaller than the sum of its proper divisors (12663034770270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013423411362 is a wasteful number, since it uses less digits than its factorization.
12013423411362 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 520042.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 12013423411362 its reverse (26311432431021), we get a palindrome (38324855842383).
The spelling of 12013423411362 in words is "twelve trillion, thirteen billion, four hundred twenty-three million, four hundred eleven thousand, three hundred sixty-two".
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