Base | Representation |
---|---|
bin | 10110011000000111… |
… | …10111100001110011 |
3 | 1011000020112001121010 |
4 | 23030003313201303 |
5 | 144100424004111 |
6 | 5304031002003 |
7 | 603464032614 |
oct | 131403674163 |
9 | 34006461533 |
10 | 12013500531 |
11 | 510534283a |
12 | 23b3369303 |
13 | 1195bb07c6 |
14 | 81d733c0b |
15 | 4a4a3aaa6 |
hex | 2cc0f7873 |
12013500531 has 16 divisors (see below), whose sum is σ = 16573708800. Its totient is φ = 7731258528.
The previous prime is 12013500523. The next prime is 12013500539. The reversal of 12013500531 is 13500531021.
It is an interprime number because it is at equal distance from previous prime (12013500523) and next prime (12013500539).
It is not a de Polignac number, because 12013500531 - 23 = 12013500523 is a prime.
It is a super-2 number, since 2×120135005312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12013500498 and 12013500507.
It is not an unprimeable number, because it can be changed into a prime (12013500539) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 544150 + ... + 565796.
It is an arithmetic number, because the mean of its divisors is an integer number (1035856800).
Almost surely, 212013500531 is an apocalyptic number.
12013500531 is a deficient number, since it is larger than the sum of its proper divisors (4560208269).
12013500531 is a wasteful number, since it uses less digits than its factorization.
12013500531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28058.
The product of its (nonzero) digits is 450, while the sum is 21.
The spelling of 12013500531 in words is "twelve billion, thirteen million, five hundred thousand, five hundred thirty-one".
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