Search a number
-
+
12022110122112 = 273334727673623
BaseRepresentation
bin1010111011110001110110…
…0110100111000010000000
31120120022011112011200102000
42232330131212213002000
53033432240142401422
641322514154424000
72350366044651636
oct256743546470200
946508145150360
1012022110122112
1139156038258a2
121421b70432000
136928ac2ba68c
142d7c32227356
1515cac9052cac
hexaef1d9a7080

12022110122112 has 256 divisors, whose sum is σ = 35606861107200. Its totient is φ = 3993274819584.

The previous prime is 12022110122051. The next prime is 12022110122123. The reversal of 12022110122112 is 21122101122021.

12022110122112 is a `hidden beast` number, since 120 + 221 + 101 + 221 + 1 + 2 = 666.

It is a super-2 number, since 2×120221101221122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3318273133 + ... + 3318276755.

It is an arithmetic number, because the mean of its divisors is an integer number (139089301200).

Almost surely, 212022110122112 is an apocalyptic number.

12022110122112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12022110122112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17803430553600).

12022110122112 is an abundant number, since it is smaller than the sum of its proper divisors (23584750985088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12022110122112 is a wasteful number, since it uses less digits than its factorization.

12022110122112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6760 (or 6742 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 12022110122112 its reverse (21122101122021), we get a palindrome (33144211244133).

Subtracting 12022110122112 from its reverse (21122101122021), we obtain a palindrome (9099990999909).

The spelling of 12022110122112 in words is "twelve trillion, twenty-two billion, one hundred ten million, one hundred twenty-two thousand, one hundred twelve".