Base | Representation |
---|---|
bin | 111000000001100001… |
… | …0010011100101010001 |
3 | 102111112121112021120201 |
4 | 1300003002103211101 |
5 | 3432343331123213 |
6 | 131134125135201 |
7 | 11456252205031 |
oct | 1600302234521 |
9 | 374477467521 |
10 | 120310020433 |
11 | 47028963059 |
12 | 1b3976ba501 |
13 | b4644b3105 |
14 | 5b745a78c1 |
15 | 31e22e36dd |
hex | 1c03093951 |
120310020433 has 16 divisors (see below), whose sum is σ = 122370640000. Its totient is φ = 118268232192.
The previous prime is 120310020409. The next prime is 120310020469. The reversal of 120310020433 is 334020013021.
It is a cyclic number.
It is not a de Polignac number, because 120310020433 - 217 = 120309889361 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 120310020433.
It is not an unprimeable number, because it can be changed into a prime (120310023433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11943523 + ... + 11953591.
It is an arithmetic number, because the mean of its divisors is an integer number (7648165000).
Almost surely, 2120310020433 is an apocalyptic number.
It is an amenable number.
120310020433 is a deficient number, since it is larger than the sum of its proper divisors (2060619567).
120310020433 is a wasteful number, since it uses less digits than its factorization.
120310020433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10984.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 120310020433 its reverse (334020013021), we get a palindrome (454330033454).
The spelling of 120310020433 in words is "one hundred twenty billion, three hundred ten million, twenty thousand, four hundred thirty-three".
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