Base | Representation |
---|---|
bin | 10001100001100111101… |
… | …010110010010100111010 |
3 | 11021010120211120121101121 |
4 | 101201213222302110322 |
5 | 124212432002043224 |
6 | 2321132301535454 |
7 | 153003265023130 |
oct | 21414752622472 |
9 | 4233524517347 |
10 | 1204330112314 |
11 | 424831a5160a |
12 | 1754a787458a |
13 | 8974c71b344 |
14 | 4240b64d750 |
15 | 214d9e1bbe4 |
hex | 11867ab253a |
1204330112314 has 16 divisors (see below), whose sum is σ = 2090699654400. Its totient is φ = 509608039824.
The previous prime is 1204330112281. The next prime is 1204330112347. The reversal of 1204330112314 is 4132110334021.
It is an interprime number because it is at equal distance from previous prime (1204330112281) and next prime (1204330112347).
It is a super-3 number, since 3×12043301123143 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 544451929 + ... + 544454140.
It is an arithmetic number, because the mean of its divisors is an integer number (130668728400).
Almost surely, 21204330112314 is an apocalyptic number.
1204330112314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1204330112314 is a deficient number, since it is larger than the sum of its proper divisors (886369542086).
1204330112314 is a wasteful number, since it uses less digits than its factorization.
1204330112314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1088906157.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1204330112314 its reverse (4132110334021), we get a palindrome (5336440446335).
The spelling of 1204330112314 in words is "one trillion, two hundred four billion, three hundred thirty million, one hundred twelve thousand, three hundred fourteen".
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