Base | Representation |
---|---|
bin | 1011000000010100000111… |
… | …1111010110110000000011 |
3 | 1120211202021220011121111010 |
4 | 2300011001333112300003 |
5 | 3041221330140001011 |
6 | 41422402124052003 |
7 | 2356125010666653 |
oct | 260050177266003 |
9 | 46752256147433 |
10 | 12100030000131 |
11 | 39456595404a7 |
12 | 1435097694003 |
13 | 69a0494a4388 |
14 | 2db904a0c363 |
15 | 15eb39ad41a6 |
hex | b0141fd6c03 |
12100030000131 has 16 divisors (see below), whose sum is σ = 16167940588800. Its totient is φ = 8049419498400.
The previous prime is 12100030000127. The next prime is 12100030000141. The reversal of 12100030000131 is 13100003000121.
It is not a de Polignac number, because 12100030000131 - 22 = 12100030000127 is a prime.
It is a super-2 number, since 2×121000300001312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12100030000111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 885736 + ... + 4998458.
It is an arithmetic number, because the mean of its divisors is an integer number (1010496286800).
Almost surely, 212100030000131 is an apocalyptic number.
12100030000131 is a deficient number, since it is larger than the sum of its proper divisors (4067910588669).
12100030000131 is a wasteful number, since it uses less digits than its factorization.
12100030000131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4114826.
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 12100030000131 its reverse (13100003000121), we get a palindrome (25200033000252).
The spelling of 12100030000131 in words is "twelve trillion, one hundred billion, thirty million, one hundred thirty-one", and thus it is an aban number.
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