Base | Representation |
---|---|
bin | 10110100010011011… |
… | …11101101001011001 |
3 | 1011020021100100222120 |
4 | 23101031331221121 |
5 | 144240102024423 |
6 | 5320401411453 |
7 | 605564404320 |
oct | 132115755131 |
9 | 34207310876 |
10 | 12100033113 |
11 | 514a175a73 |
12 | 2418339b89 |
13 | 11aaaba40c |
14 | 82b01b0b7 |
15 | 4ac42eee3 |
hex | 2d137da59 |
12100033113 has 16 divisors (see below), whose sum is σ = 18750658560. Its totient is φ = 6797112336.
The previous prime is 12100033081. The next prime is 12100033133. The reversal of 12100033113 is 31133000121.
It is not a de Polignac number, because 12100033113 - 25 = 12100033081 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12100033092 and 12100033101.
It is not an unprimeable number, because it can be changed into a prime (12100033133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4881745 + ... + 4884222.
It is an arithmetic number, because the mean of its divisors is an integer number (1171916160).
Almost surely, 212100033113 is an apocalyptic number.
It is an amenable number.
12100033113 is a deficient number, since it is larger than the sum of its proper divisors (6650625447).
12100033113 is an equidigital number, since it uses as much as digits as its factorization.
12100033113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9766036.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 12100033113 its reverse (31133000121), we get a palindrome (43233033234).
The spelling of 12100033113 in words is "twelve billion, one hundred million, thirty-three thousand, one hundred thirteen".
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