Base | Representation |
---|---|
bin | 1011000000011000100011… |
… | …1010111000111111100011 |
3 | 1120211212100211101110212220 |
4 | 2300012020322320333203 |
5 | 3041231244310341003 |
6 | 41423120154122123 |
7 | 2356166340635223 |
oct | 260061072707743 |
9 | 46755324343786 |
10 | 12101220012003 |
11 | 394610a244a91 |
12 | 143536a120343 |
13 | 69a1a8bac505 |
14 | 2db9b8a9c083 |
15 | 15eba92ea353 |
hex | b0188eb8fe3 |
12101220012003 has 16 divisors (see below), whose sum is σ = 16252541222400. Its totient is φ = 8008700136480.
The previous prime is 12101220011957. The next prime is 12101220012041. The reversal of 12101220012003 is 30021002210121.
12101220012003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12101220012003 - 217 = 12101219880931 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12101220012043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3193078 + ... + 5864996.
It is an arithmetic number, because the mean of its divisors is an integer number (1015783826400).
Almost surely, 212101220012003 is an apocalyptic number.
12101220012003 is a deficient number, since it is larger than the sum of its proper divisors (4151321210397).
12101220012003 is a wasteful number, since it uses less digits than its factorization.
12101220012003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2682922.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 12101220012003 its reverse (30021002210121), we get a palindrome (42122222222124).
The spelling of 12101220012003 in words is "twelve trillion, one hundred one billion, two hundred twenty million, twelve thousand, three".
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