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1211012020113 = 37230392503027
BaseRepresentation
bin10001100111110101111…
…100001111011110010001
311021202211111202200201020
4101213311330033132101
5124320123034120423
62324155314230053
7153331002220650
oct21476574173621
94252744680636
101211012020113
11427650794865
12176851585329
138a275b6053c
1442882c47197
152177b8514e3
hex119f5f0f791

1211012020113 has 16 divisors (see below), whose sum is σ = 1845432483840. Its totient is φ = 691976555856.

The previous prime is 1211012020109. The next prime is 1211012020123. The reversal of 1211012020113 is 3110202101121.

It is not a de Polignac number, because 1211012020113 - 22 = 1211012020109 is a prime.

It is a super-2 number, since 2×12110120201132 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211012020092 and 1211012020101.

It is not an unprimeable number, because it can be changed into a prime (1211012020123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 767695 + ... + 1735332.

It is an arithmetic number, because the mean of its divisors is an integer number (115339530240).

Almost surely, 21211012020113 is an apocalyptic number.

It is an amenable number.

1211012020113 is a deficient number, since it is larger than the sum of its proper divisors (634420463727).

1211012020113 is a wasteful number, since it uses less digits than its factorization.

1211012020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2526076.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1211012020113 its reverse (3110202101121), we get a palindrome (4321214121234).

The spelling of 1211012020113 in words is "one trillion, two hundred eleven billion, twelve million, twenty thousand, one hundred thirteen".

Divisors: 1 3 7 21 23039 69117 161273 483819 2503027 7509081 17521189 52563567 57667239053 173001717159 403670673371 1211012020113