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12114012000003 = 353456116704397
BaseRepresentation
bin1011000001001000001101…
…1000011100111100000011
31120220002101022202210112020
42300102003120130330003
53041433444033000003
641433033354532523
72360131340015664
oct260220330347403
946802338683466
1012114012000003
113950583a649a1
12143793a137143
1369b467150194
142dc46d95b36b
151601a735dd53
hexb048361cf03

12114012000003 has 16 divisors (see below), whose sum is σ = 16460380154016. Its totient is φ = 7921892759040.

The previous prime is 12114012000001. The next prime is 12114012000011. The reversal of 12114012000003 is 30000021041121.

It is not a de Polignac number, because 12114012000003 - 21 = 12114012000001 is a prime.

It is a super-3 number, since 3×121140120000033 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (12114012000001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7627000 + ... + 9077397.

It is an arithmetic number, because the mean of its divisors is an integer number (1028773759626).

Almost surely, 212114012000003 is an apocalyptic number.

12114012000003 is a deficient number, since it is larger than the sum of its proper divisors (4346368154013).

12114012000003 is a wasteful number, since it uses less digits than its factorization.

12114012000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16709014.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12114012000003 its reverse (30000021041121), we get a palindrome (42114033041124).

The spelling of 12114012000003 in words is "twelve trillion, one hundred fourteen billion, twelve million, three", and thus it is an aban number.

Divisors: 1 3 53 159 4561 13683 241733 725199 16704397 50113191 885333041 2655999123 76188754717 228566264151 4038004000001 12114012000003