Base | Representation |
---|---|
bin | 10001101000110110110… |
… | …111001000100011110001 |
3 | 11021212122102020202210020 |
4 | 101220312313020203301 |
5 | 124324340401400423 |
6 | 2324455343154053 |
7 | 153366666130566 |
oct | 21506667104361 |
9 | 4255572222706 |
10 | 1212101200113 |
11 | 42805a589921 |
12 | 176ab62a5929 |
13 | 8a3ba6c334b |
14 | 4294776a86d |
15 | 217e229b4e3 |
hex | 11a36dc88f1 |
1212101200113 has 16 divisors (see below), whose sum is σ = 1617375191040. Its totient is φ = 807447477456.
The previous prime is 1212101200073. The next prime is 1212101200147. The reversal of 1212101200113 is 3110021012121.
It is not a de Polignac number, because 1212101200113 - 212 = 1212101196017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1212101200092 and 1212101200101.
It is not an unprimeable number, because it can be changed into a prime (1212101200813) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57525006 + ... + 57546072.
It is an arithmetic number, because the mean of its divisors is an integer number (101085949440).
Almost surely, 21212101200113 is an apocalyptic number.
It is an amenable number.
1212101200113 is a deficient number, since it is larger than the sum of its proper divisors (405273990927).
1212101200113 is a wasteful number, since it uses less digits than its factorization.
1212101200113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34876.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1212101200113 its reverse (3110021012121), we get a palindrome (4322122212234).
The spelling of 1212101200113 in words is "one trillion, two hundred twelve billion, one hundred one million, two hundred thousand, one hundred thirteen".
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