12124011331 has 16 divisors (see below), whose sum is σ = 12489424000. Its totient is φ = 11764450368.

The previous prime is 12124011311. The next prime is 12124011373. The reversal of 12124011331 is 13311042121.

It is a cyclic number.

It is not a de Polignac number, because 12124011331 - 2⁵ = 12124011299 is a prime.

It is a super-3 number, since 3×12124011331³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12124011299 and 12124011308.

It is not an unprimeable number, because it can be changed into a prime (12124011301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7135120 + ... + 7136818.

It is an arithmetic number, because the mean of its divisors is an integer number (780589000).

Almost surely, 2^12124011331 is an apocalyptic number.

12124011331 is a deficient number, since it is larger than the sum of its proper divisors (365412669).

12124011331 is a wasteful number, since it uses less digits than its factorization.

12124011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3298.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12124011331 its reverse (13311042121), we get a palindrome (25435053452).

The spelling of 12124011331 in words is "twelve billion, one hundred twenty-four million, eleven thousand, three hundred thirty-one".