Base | Representation |
---|---|
bin | 10001101001101100100… |
… | …100100110110111110011 |
3 | 11021221222012212001120010 |
4 | 101221230210212313303 |
5 | 124333212043010303 |
6 | 2325125013150003 |
7 | 153431220353502 |
oct | 21515444466763 |
9 | 4257865761503 |
10 | 1213002313203 |
11 | 42848220148a |
12 | 17710802b303 |
13 | 8a5022b9565 |
14 | 429d12d6839 |
15 | 21846447c03 |
hex | 11a6c926df3 |
1213002313203 has 32 divisors (see below), whose sum is σ = 1682350179840. Its totient is φ = 776788266240.
The previous prime is 1213002313169. The next prime is 1213002313231. The reversal of 1213002313203 is 3023132003121.
It is not a de Polignac number, because 1213002313203 - 212 = 1213002309107 is a prime.
It is a super-2 number, since 2×12130023132032 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1213002313203.
It is not an unprimeable number, because it can be changed into a prime (1213002363203) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 97010650 + ... + 97023152.
It is an arithmetic number, because the mean of its divisors is an integer number (52573443120).
Almost surely, 21213002313203 is an apocalyptic number.
1213002313203 is a deficient number, since it is larger than the sum of its proper divisors (469347866637).
1213002313203 is a wasteful number, since it uses less digits than its factorization.
1213002313203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24939.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1213002313203 its reverse (3023132003121), we get a palindrome (4236134316324).
The spelling of 1213002313203 in words is "one trillion, two hundred thirteen billion, two million, three hundred thirteen thousand, two hundred three".
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