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12141425301433 = 3831013122925463
BaseRepresentation
bin1011000010101110010101…
…0101111001011110111001
31120222201010210201210112121
42300223211111321132321
53042411114334121213
641453405505041241
72362121560153411
oct260534525713671
946881123653477
1012141425301433
11396117106900a
12144110a926221
136a0c1564b7bc
142dd910627641
15160c5dd3388d
hexb0ae55797b9

12141425301433 has 16 divisors (see below), whose sum is σ = 12195536670720. Its totient is φ = 12087451820224.

The previous prime is 12141425301361. The next prime is 12141425301443. The reversal of 12141425301433 is 33410352414121.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12141425301433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12141425301443) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 476813460 + ... + 476838922.

It is an arithmetic number, because the mean of its divisors is an integer number (762221041920).

Almost surely, 212141425301433 is an apocalyptic number.

It is an amenable number.

12141425301433 is a deficient number, since it is larger than the sum of its proper divisors (54111369287).

12141425301433 is a wasteful number, since it uses less digits than its factorization.

12141425301433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28088.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 12141425301433 its reverse (33410352414121), we get a palindrome (45551777715554).

The spelling of 12141425301433 in words is "twelve trillion, one hundred forty-one billion, four hundred twenty-five million, three hundred one thousand, four hundred thirty-three".

Divisors: 1 383 1013 1229 25463 387979 470707 1244977 9752329 25794019 31294027 476826191 9879109277 11985612341 31700849351 12141425301433