Base | Representation |
---|---|
bin | 1011000010111000000101… |
… | …1000110110101100101001 |
3 | 1120222221220021000000210222 |
4 | 2300232001120312230221 |
5 | 3042432000042302103 |
6 | 41454521350215425 |
7 | 2362243500031031 |
oct | 260560130665451 |
9 | 46887807000728 |
10 | 12144043322153 |
11 | 39622949517a6 |
12 | 144171b654575 |
13 | 6a1241b60ca2 |
14 | 2ddabc1da8c1 |
15 | 160d63ac3638 |
hex | b0b81636b29 |
12144043322153 has 16 divisors (see below), whose sum is σ = 12578736542400. Its totient is φ = 11710415196480.
The previous prime is 12144043322107. The next prime is 12144043322167. The reversal of 12144043322153 is 35122334044121.
It is a cyclic number.
It is not a de Polignac number, because 12144043322153 - 232 = 12139748354857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12144043321153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 321158618 + ... + 321196428.
It is an arithmetic number, because the mean of its divisors is an integer number (786171033900).
Almost surely, 212144043322153 is an apocalyptic number.
It is an amenable number.
12144043322153 is a deficient number, since it is larger than the sum of its proper divisors (434693220247).
12144043322153 is a wasteful number, since it uses less digits than its factorization.
12144043322153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51592.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 12144043322153 its reverse (35122334044121), we get a palindrome (47266377366274).
The spelling of 12144043322153 in words is "twelve trillion, one hundred forty-four billion, forty-three million, three hundred twenty-two thousand, one hundred fifty-three".
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