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12211332433 = 193314394423
BaseRepresentation
bin10110101111101101…
…00010010101010001
31011112000202221221121
423113312202111101
5200002100114213
65335415122241
7611415420166
oct132766422521
934460687847
1012211332433
1151a6a84883
122449673381
1311c7b88cc1
1483bb1006d
154b70b788d
hex2d7da2551

12211332433 has 16 divisors (see below), whose sum is σ = 12925158400. Its totient is φ = 11504805840.

The previous prime is 12211332409. The next prime is 12211332449. The reversal of 12211332433 is 33423311221.

It is a cyclic number.

It is not a de Polignac number, because 12211332433 - 213 = 12211324241 is a prime.

It is a super-4 number, since 4×122113324334 (a number of 41 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12211332398 and 12211332407.

It is not an unprimeable number, because it can be changed into a prime (12211332403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2758660 + ... + 2763082.

It is an arithmetic number, because the mean of its divisors is an integer number (807822400).

Almost surely, 212211332433 is an apocalyptic number.

It is an amenable number.

12211332433 is a deficient number, since it is larger than the sum of its proper divisors (713825967).

12211332433 is a wasteful number, since it uses less digits than its factorization.

12211332433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5212.

The product of its digits is 2592, while the sum is 25.

Adding to 12211332433 its reverse (33423311221), we get a palindrome (45634643654).

The spelling of 12211332433 in words is "twelve billion, two hundred eleven million, three hundred thirty-two thousand, four hundred thirty-three".

Divisors: 1 19 331 439 4423 6289 8341 84037 145309 1464013 1941697 2760871 27816247 36892243 642701707 12211332433