Base | Representation |
---|---|
bin | 10110101111101101… |
… | …00010010101010001 |
3 | 1011112000202221221121 |
4 | 23113312202111101 |
5 | 200002100114213 |
6 | 5335415122241 |
7 | 611415420166 |
oct | 132766422521 |
9 | 34460687847 |
10 | 12211332433 |
11 | 51a6a84883 |
12 | 2449673381 |
13 | 11c7b88cc1 |
14 | 83bb1006d |
15 | 4b70b788d |
hex | 2d7da2551 |
12211332433 has 16 divisors (see below), whose sum is σ = 12925158400. Its totient is φ = 11504805840.
The previous prime is 12211332409. The next prime is 12211332449. The reversal of 12211332433 is 33423311221.
It is a cyclic number.
It is not a de Polignac number, because 12211332433 - 213 = 12211324241 is a prime.
It is a super-4 number, since 4×122113324334 (a number of 41 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12211332398 and 12211332407.
It is not an unprimeable number, because it can be changed into a prime (12211332403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2758660 + ... + 2763082.
It is an arithmetic number, because the mean of its divisors is an integer number (807822400).
Almost surely, 212211332433 is an apocalyptic number.
It is an amenable number.
12211332433 is a deficient number, since it is larger than the sum of its proper divisors (713825967).
12211332433 is a wasteful number, since it uses less digits than its factorization.
12211332433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5212.
The product of its digits is 2592, while the sum is 25.
Adding to 12211332433 its reverse (33423311221), we get a palindrome (45634643654).
The spelling of 12211332433 in words is "twelve billion, two hundred eleven million, three hundred thirty-two thousand, four hundred thirty-three".
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