Base | Representation |
---|---|
bin | 1011001000100010000010… |
… | …1000010110010000011001 |
3 | 1121100020200120102010110220 |
4 | 2302020200220112100121 |
5 | 3101024441241211213 |
6 | 42011310454030253 |
7 | 2402253311152206 |
oct | 262104050262031 |
9 | 47306616363426 |
10 | 12241204241433 |
11 | 399a5137374a2 |
12 | 1458516648389 |
13 | 6aa45740c1bb |
14 | 304698182cad |
15 | 16364d953e23 |
hex | b2220a16419 |
12241204241433 has 16 divisors (see below), whose sum is σ = 16519941881856. Its totient is φ = 8061654838160.
The previous prime is 12241204241429. The next prime is 12241204241471. The reversal of 12241204241433 is 33414240214221.
It is a cyclic number.
It is not a de Polignac number, because 12241204241433 - 22 = 12241204241429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12241204241394 and 12241204241403.
It is not an unprimeable number, because it can be changed into a prime (12241204241423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72585 + ... + 4948502.
It is an arithmetic number, because the mean of its divisors is an integer number (1032496367616).
Almost surely, 212241204241433 is an apocalyptic number.
It is an amenable number.
12241204241433 is a deficient number, since it is larger than the sum of its proper divisors (4278737640423).
12241204241433 is an equidigital number, since it uses as much as digits as its factorization.
12241204241433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5030964.
The product of its (nonzero) digits is 36864, while the sum is 33.
Adding to 12241204241433 its reverse (33414240214221), we get a palindrome (45655444455654).
The spelling of 12241204241433 in words is "twelve trillion, two hundred forty-one billion, two hundred four million, two hundred forty-one thousand, four hundred thirty-three".
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