Base | Representation |
---|---|
bin | 1011001001001011110000… |
… | …0001110010001010111010 |
3 | 1121101022120220200021022120 |
4 | 2302102330001302022322 |
5 | 3101220404213444232 |
6 | 42020401522102110 |
7 | 2403130632533124 |
oct | 262227401621272 |
9 | 47338526607276 |
10 | 12252401312442 |
11 | 39a423a137695 |
12 | 145a7204aa936 |
13 | 6ab5201068c5 |
14 | 30503b2b2214 |
15 | 163aa696e92c |
hex | b24bc0722ba |
12252401312442 has 16 divisors (see below), whose sum is σ = 24540265444512. Its totient is φ = 4078223300880.
The previous prime is 12252401312419. The next prime is 12252401312471. The reversal of 12252401312442 is 24421310425221.
It is a super-3 number, since 3×122524013124423 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1477612993 + ... + 1477621284.
It is an arithmetic number, because the mean of its divisors is an integer number (1533766590282).
Almost surely, 212252401312442 is an apocalyptic number.
12252401312442 is an abundant number, since it is smaller than the sum of its proper divisors (12287864132070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12252401312442 is a wasteful number, since it uses less digits than its factorization.
12252401312442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2955234973.
The product of its (nonzero) digits is 30720, while the sum is 33.
Adding to 12252401312442 its reverse (24421310425221), we get a palindrome (36673711737663).
The spelling of 12252401312442 in words is "twelve trillion, two hundred fifty-two billion, four hundred one million, three hundred twelve thousand, four hundred forty-two".
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