Base | Representation |
---|---|
bin | 1011010011101110001011… |
… | …1110101000110000100001 |
3 | 1122000121220001100111200020 |
4 | 2310323202332220300201 |
5 | 3112202143004102223 |
6 | 42235502310544053 |
7 | 2422200214232151 |
oct | 264734276506041 |
9 | 48017801314606 |
10 | 12433443425313 |
11 | 3a63aa2746679 |
12 | 1489827068029 |
13 | 6c2612911791 |
14 | 30dad365c761 |
15 | 1686508c71e3 |
hex | b4ee2fa8c21 |
12433443425313 has 16 divisors (see below), whose sum is σ = 17451697793280. Its totient is φ = 7852138214544.
The previous prime is 12433443425287. The next prime is 12433443425317. The reversal of 12433443425313 is 31352434433421.
12433443425313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12433443425313 - 210 = 12433443424289 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12433443425317) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7015131 + ... + 8606912.
It is an arithmetic number, because the mean of its divisors is an integer number (1090731112080).
Almost surely, 212433443425313 is an apocalyptic number.
It is an amenable number.
12433443425313 is a deficient number, since it is larger than the sum of its proper divisors (5018254367967).
12433443425313 is a wasteful number, since it uses less digits than its factorization.
12433443425313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15636028.
The product of its digits is 1244160, while the sum is 42.
Adding to 12433443425313 its reverse (31352434433421), we get a palindrome (43785877858734).
The spelling of 12433443425313 in words is "twelve trillion, four hundred thirty-three billion, four hundred forty-three million, four hundred twenty-five thousand, three hundred thirteen".
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