Base | Representation |
---|---|
bin | 1011010111110110010001… |
… | …1001111110110010000011 |
3 | 1122021101212120002122102011 |
4 | 2311331210121332302003 |
5 | 3114332334042043021 |
6 | 42332224545033351 |
7 | 2430260030052415 |
oct | 265754431766203 |
9 | 48241776078364 |
10 | 12504334331011 |
11 | 3a91070819346 |
12 | 149b510325857 |
13 | 6c91cc7ba263 |
14 | 3132da7049b5 |
15 | 16a3ee319de1 |
hex | b5f6467ec83 |
12504334331011 has 16 divisors (see below), whose sum is σ = 13346097020928. Its totient is φ = 11695488206400.
The previous prime is 12504334330927. The next prime is 12504334331023. The reversal of 12504334331011 is 11013343340521.
It is a cyclic number.
It is not a de Polignac number, because 12504334331011 - 211 = 12504334328963 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12504334331611) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45836835 + ... + 46108828.
It is an arithmetic number, because the mean of its divisors is an integer number (834131063808).
Almost surely, 212504334331011 is an apocalyptic number.
12504334331011 is a deficient number, since it is larger than the sum of its proper divisors (841762689917).
12504334331011 is a wasteful number, since it uses less digits than its factorization.
12504334331011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91945842.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 12504334331011 its reverse (11013343340521), we get a palindrome (23517677671532).
The spelling of 12504334331011 in words is "twelve trillion, five hundred four billion, three hundred thirty-four million, three hundred thirty-one thousand, eleven".
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