Base | Representation |
---|---|
bin | 11100011011110000110001… |
… | …101111111110100110111011 |
3 | 121101202221220201112011211221 |
4 | 130123300301233332212323 |
5 | 112342332223211414011 |
6 | 1121544334023132511 |
7 | 35224534312266151 |
oct | 3433606157764673 |
9 | 541687821464757 |
10 | 125053102451131 |
11 | 369337a522a218 |
12 | 12038166ba4137 |
13 | 54a15c2c3654a |
14 | 22c48611bb3d1 |
15 | e6cdb8c9b971 |
hex | 71bc31bfe9bb |
125053102451131 has 16 divisors (see below), whose sum is σ = 125712248622048. Its totient is φ = 124395144307200.
The previous prime is 125053102451129. The next prime is 125053102451171. The reversal of 125053102451131 is 131154201350521.
It is a cyclic number.
It is not a de Polignac number, because 125053102451131 - 21 = 125053102451129 is a prime.
It is a super-2 number, since 2×1250531024511312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125053102451171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2578868796 + ... + 2578917286.
It is an arithmetic number, because the mean of its divisors is an integer number (7857015538878).
Almost surely, 2125053102451131 is an apocalyptic number.
125053102451131 is a deficient number, since it is larger than the sum of its proper divisors (659146170917).
125053102451131 is a wasteful number, since it uses less digits than its factorization.
125053102451131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60462.
The product of its (nonzero) digits is 18000, while the sum is 34.
The spelling of 125053102451131 in words is "one hundred twenty-five trillion, fifty-three billion, one hundred two million, four hundred fifty-one thousand, one hundred thirty-one".
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