12525140403 has 20 divisors (see below), whose sum is σ = 19108494240. Its totient is φ = 8172429552.

The previous prime is 12525140401. The next prime is 12525140413. The reversal of 12525140403 is 30404152521.

12525140403 is a `hidden beast` number, since 1 + 2 + 5 + 251 + 4 + 0 + 403 = 666.

It is not a de Polignac number, because 12525140403 - 2¹ = 12525140401 is a prime.

It is a super-2 number, since 2×12525140403² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (12525140401) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 1641208 + ... + 1648821.

It is an arithmetic number, because the mean of its divisors is an integer number (955424712).

Almost surely, 2^12525140403 is an apocalyptic number.

12525140403 is a deficient number, since it is larger than the sum of its proper divisors (6583353837).

12525140403 is an equidigital number, since it uses as much as digits as its factorization.

12525140403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3290088 (or 3290079 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 27.

Adding to 12525140403 its reverse (30404152521), we get a palindrome (42929292924).

The spelling of 12525140403 in words is "twelve billion, five hundred twenty-five million, one hundred forty thousand, four hundred three".