Base | Representation |
---|---|
bin | 11101100011110001111011… |
… | …100100111111100011100001 |
3 | 122001022002020220012211002020 |
4 | 131203301323210333203201 |
5 | 114014423342203113101 |
6 | 1140254054334412053 |
7 | 36245226206326413 |
oct | 3543617344774341 |
9 | 561262226184066 |
10 | 130002143410401 |
11 | 38471665896189 |
12 | 126b7352961029 |
13 | 57701c3661c72 |
14 | 24161ccb089b3 |
15 | 10069c2838136 |
hex | 763c7b93f8e1 |
130002143410401 has 16 divisors (see below), whose sum is σ = 178455408189696. Its totient is φ = 84133217636496.
The previous prime is 130002143410343. The next prime is 130002143410411. The reversal of 130002143410401 is 104014341200031.
It is not a de Polignac number, because 130002143410401 - 27 = 130002143410273 is a prime.
It is a super-2 number, since 2×1300021434104012 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130002143410411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3091293555 + ... + 3091335608.
It is an arithmetic number, because the mean of its divisors is an integer number (11153463011856).
Almost surely, 2130002143410401 is an apocalyptic number.
It is an amenable number.
130002143410401 is a deficient number, since it is larger than the sum of its proper divisors (48453264779295).
130002143410401 is a wasteful number, since it uses less digits than its factorization.
130002143410401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6182629372.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 130002143410401 its reverse (104014341200031), we get a palindrome (234016484610432).
The spelling of 130002143410401 in words is "one hundred thirty trillion, two billion, one hundred forty-three million, four hundred ten thousand, four hundred one".
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