Base | Representation |
---|---|
bin | 111100100010101000… |
… | …0111111111100111001 |
3 | 110102120200211100010021 |
4 | 1321011100333330321 |
5 | 4112230320244113 |
6 | 135420513050441 |
7 | 12251540066500 |
oct | 1710520777471 |
9 | 412520740107 |
10 | 130011103033 |
11 | 50156972a99 |
12 | 21244556a21 |
13 | c34c291486 |
14 | 6414b59837 |
15 | 35add0848d |
hex | 1e4543ff39 |
130011103033 has 48 divisors (see below), whose sum is σ = 156372249600. Its totient is φ = 107710149120.
The previous prime is 130011103009. The next prime is 130011103039. The reversal of 130011103033 is 330301110031.
It is a de Polignac number, because none of the positive numbers 2k-130011103033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130011102998 and 130011103016.
It is not an unprimeable number, because it can be changed into a prime (130011103039) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 160705533 + ... + 160706341.
It is an arithmetic number, because the mean of its divisors is an integer number (3257755200).
Almost surely, 2130011103033 is an apocalyptic number.
It is an amenable number.
130011103033 is a deficient number, since it is larger than the sum of its proper divisors (26361146567).
130011103033 is a wasteful number, since it uses less digits than its factorization.
130011103033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1510 (or 1503 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 130011103033 its reverse (330301110031), we get a palindrome (460312213064).
The spelling of 130011103033 in words is "one hundred thirty billion, eleven million, one hundred three thousand, thirty-three".
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