Base | Representation |
---|---|
bin | 11101100100000100101110… |
… | …010100001111101111101001 |
3 | 122001101000100011210221110011 |
4 | 131210010232110033233221 |
5 | 114020241203413323423 |
6 | 1140311232524051521 |
7 | 36246542230523200 |
oct | 3544045624175751 |
9 | 561330304727404 |
10 | 130022322011113 |
11 | 3847a1801115a4 |
12 | 126bb244693ba1 |
13 | 577208b04089c |
14 | 2417184a02237 |
15 | 10072a40d2b0d |
hex | 76412e50fbe9 |
130022322011113 has 48 divisors (see below), whose sum is σ = 156518762400000. Its totient is φ = 107624621922048.
The previous prime is 130022322011089. The next prime is 130022322011129. The reversal of 130022322011113 is 311110223220031.
It is not a de Polignac number, because 130022322011113 - 25 = 130022322011081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130022322011213) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4875397143 + ... + 4875423811.
It is an arithmetic number, because the mean of its divisors is an integer number (3260807550000).
Almost surely, 2130022322011113 is an apocalyptic number.
It is an amenable number.
130022322011113 is a deficient number, since it is larger than the sum of its proper divisors (26496440388887).
130022322011113 is a wasteful number, since it uses less digits than its factorization.
130022322011113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52814 (or 52807 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 130022322011113 its reverse (311110223220031), we get a palindrome (441132545231144).
The spelling of 130022322011113 in words is "one hundred thirty trillion, twenty-two billion, three hundred twenty-two million, eleven thousand, one hundred thirteen".
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