Base | Representation |
---|---|
bin | 11101100100000101011101… |
… | …100011000110001100100010 |
3 | 122001101002101101220011100120 |
4 | 131210011131203012030202 |
5 | 114020244314243331224 |
6 | 1140311443312301110 |
7 | 36246600662146044 |
oct | 3544053543061442 |
9 | 561332341804316 |
10 | 130023114433314 |
11 | 3847a547447083 |
12 | 126bb425b41796 |
13 | 577218626c56b |
14 | 241721bd57a94 |
15 | 10072ed95e779 |
hex | 76415d8c6322 |
130023114433314 has 32 divisors (see below), whose sum is σ = 265580005706496. Its totient is φ = 42418748104320.
The previous prime is 130023114433297. The next prime is 130023114433319. The reversal of 130023114433314 is 413334411320031.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (130023114433319) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116661774 + ... + 117771030.
It is an arithmetic number, because the mean of its divisors is an integer number (8299375178328).
Almost surely, 2130023114433314 is an apocalyptic number.
130023114433314 is an abundant number, since it is smaller than the sum of its proper divisors (135556891273182).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130023114433314 is a wasteful number, since it uses less digits than its factorization.
130023114433314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1524970.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 130023114433314 its reverse (413334411320031), we get a palindrome (543357525753345).
The spelling of 130023114433314 in words is "one hundred thirty trillion, twenty-three billion, one hundred fourteen million, four hundred thirty-three thousand, three hundred fourteen".
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