Base | Representation |
---|---|
bin | 111100100011001110… |
… | …0111001101100000001 |
3 | 110102122002021020001212 |
4 | 1321012130321230001 |
5 | 4112300414002241 |
6 | 135422503335505 |
7 | 12252201160205 |
oct | 1710634715401 |
9 | 412562236055 |
10 | 130031000321 |
11 | 50167123132 |
12 | 2124b151595 |
13 | c353439c11 |
14 | 6417658b05 |
15 | 35b0938beb |
hex | 1e46739b01 |
130031000321 has 16 divisors (see below), whose sum is σ = 138144014400. Its totient is φ = 122045833728.
The previous prime is 130031000317. The next prime is 130031000339. The reversal of 130031000321 is 123000130031.
It is a cyclic number.
It is not a de Polignac number, because 130031000321 - 22 = 130031000317 is a prime.
It is a super-2 number, since 2×1300310003212 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130031000296 and 130031000305.
It is not an unprimeable number, because it can be changed into a prime (130031000381) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5697485 + ... + 5720261.
It is an arithmetic number, because the mean of its divisors is an integer number (8634000900).
Almost surely, 2130031000321 is an apocalyptic number.
It is an amenable number.
130031000321 is a deficient number, since it is larger than the sum of its proper divisors (8113014079).
130031000321 is a wasteful number, since it uses less digits than its factorization.
130031000321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25568.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 130031000321 its reverse (123000130031), we get a palindrome (253031130352).
The spelling of 130031000321 in words is "one hundred thirty billion, thirty-one million, three hundred twenty-one", and thus it is an aban number.
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