Base | Representation |
---|---|
bin | 11101100100100011001010… |
… | …111011110111010000001001 |
3 | 122001111010201120100001022120 |
4 | 131210203022323313100021 |
5 | 114021310132142211241 |
6 | 1140334240535441453 |
7 | 36252110332412154 |
oct | 3544431273672011 |
9 | 561433646301276 |
10 | 130055014413321 |
11 | 38492027122218 |
12 | 12705649226289 |
13 | 577519b15c08a |
14 | 24189a6862c9b |
15 | 1008069290666 |
hex | 7648caef7409 |
130055014413321 has 16 divisors (see below), whose sum is σ = 179000826961920. Its totient is φ = 83906284185360.
The previous prime is 130055014413319. The next prime is 130055014413329. The reversal of 130055014413321 is 123314410550031.
130055014413321 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 130055014413321 - 21 = 130055014413319 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130055014413329) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54155946 + ... + 56506428.
It is an arithmetic number, because the mean of its divisors is an integer number (11187551685120).
Almost surely, 2130055014413321 is an apocalyptic number.
It is an amenable number.
130055014413321 is a deficient number, since it is larger than the sum of its proper divisors (48945812548599).
130055014413321 is a wasteful number, since it uses less digits than its factorization.
130055014413321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2945476.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 130055014413321 its reverse (123314410550031), we get a palindrome (253369424963352).
The spelling of 130055014413321 in words is "one hundred thirty trillion, fifty-five billion, fourteen million, four hundred thirteen thousand, three hundred twenty-one".
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