Base | Representation |
---|---|
bin | 1011110101000011111111… |
… | …0111111111110101000001 |
3 | 1201001101100201021020110122 |
4 | 2331100333313333311001 |
5 | 3201043231022210012 |
6 | 43354551503110025 |
7 | 2511445366100306 |
oct | 275207767776501 |
9 | 51041321236418 |
10 | 13006232616257 |
11 | 4164a04270621 |
12 | 1560840ba2315 |
13 | 734636cbb22a |
14 | 32d70daa70ad |
15 | 1784c691ce72 |
hex | bd43fdffd41 |
13006232616257 has 16 divisors (see below), whose sum is σ = 13456956936192. Its totient is φ = 12557482814160.
The previous prime is 13006232616241. The next prime is 13006232616277. The reversal of 13006232616257 is 75261623260031.
It is a cyclic number.
It is not a de Polignac number, because 13006232616257 - 24 = 13006232616241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13006232616227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29386868 + ... + 29826170.
It is an arithmetic number, because the mean of its divisors is an integer number (841059808512).
Almost surely, 213006232616257 is an apocalyptic number.
It is an amenable number.
13006232616257 is a deficient number, since it is larger than the sum of its proper divisors (450724319935).
13006232616257 is a wasteful number, since it uses less digits than its factorization.
13006232616257 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 441548.
The product of its (nonzero) digits is 544320, while the sum is 44.
Adding to 13006232616257 its reverse (75261623260031), we get a palindrome (88267855876288).
The spelling of 13006232616257 in words is "thirteen trillion, six billion, two hundred thirty-two million, six hundred sixteen thousand, two hundred fifty-seven".
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