Base | Representation |
---|---|
bin | 11000001110111011… |
… | …01011110111010011 |
3 | 1020120200211210022110 |
4 | 30013131223313103 |
5 | 203121042433433 |
6 | 5550552040403 |
7 | 640255142244 |
oct | 140735536723 |
9 | 36520753273 |
10 | 13010124243 |
11 | 557696a9a6 |
12 | 2631093103 |
13 | 12c4507c8c |
14 | 8b5c42ccb |
15 | 5122a1963 |
hex | 30776bdd3 |
13010124243 has 16 divisors (see below), whose sum is σ = 17573760000. Its totient is φ = 8560044480.
The previous prime is 13010124241. The next prime is 13010124251. The reversal of 13010124243 is 34242101031.
It is not a de Polignac number, because 13010124243 - 21 = 13010124241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13010124241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 632383 + ... + 652631.
It is an arithmetic number, because the mean of its divisors is an integer number (1098360000).
Almost surely, 213010124243 is an apocalyptic number.
13010124243 is a deficient number, since it is larger than the sum of its proper divisors (4563635757).
13010124243 is a wasteful number, since it uses less digits than its factorization.
13010124243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23042.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 13010124243 its reverse (34242101031), we get a palindrome (47252225274).
The spelling of 13010124243 in words is "thirteen billion, ten million, one hundred twenty-four thousand, two hundred forty-three".
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