Base | Representation |
---|---|
bin | 11101100101011000011011… |
… | …101010001100110000000011 |
3 | 122001200121100011100010011220 |
4 | 131211120123222030300003 |
5 | 114023224243021442011 |
6 | 1140420415424210123 |
7 | 36256203456134445 |
oct | 3545303352146003 |
9 | 561617304303156 |
10 | 130112203312131 |
11 | 3850430382a357 |
12 | 12714749769943 |
13 | 577a6b33a3181 |
14 | 241b66dc42495 |
15 | 10097b4d14506 |
hex | 76561ba8cc03 |
130112203312131 has 32 divisors (see below), whose sum is σ = 179254683514368. Its totient is φ = 83884187393280.
The previous prime is 130112203312129. The next prime is 130112203312163. The reversal of 130112203312131 is 131213302211031.
It is not a de Polignac number, because 130112203312131 - 21 = 130112203312129 is a prime.
It is a super-2 number, since 2×1301122033121312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130112203312111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 209547376 + ... + 210167378.
It is an arithmetic number, because the mean of its divisors is an integer number (5601708859824).
Almost surely, 2130112203312131 is an apocalyptic number.
130112203312131 is a deficient number, since it is larger than the sum of its proper divisors (49142480202237).
130112203312131 is a wasteful number, since it uses less digits than its factorization.
130112203312131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 631531.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 130112203312131 its reverse (131213302211031), we get a palindrome (261325505523162).
The spelling of 130112203312131 in words is "one hundred thirty trillion, one hundred twelve billion, two hundred three million, three hundred twelve thousand, one hundred thirty-one".
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