Base | Representation |
---|---|
bin | 1011110101010111101101… |
… | …0110100011111010101010 |
3 | 1201001220000120200010101010 |
4 | 2331111323112203322222 |
5 | 3201140101003421214 |
6 | 43401225015004350 |
7 | 2512023505333536 |
oct | 275257326437252 |
9 | 51056016603333 |
10 | 13011525451434 |
11 | 416717a9a8a74 |
12 | 15618796696b6 |
13 | 734c9b709673 |
14 | 32da929d4bc6 |
15 | 1786d641a659 |
hex | bd57b5a3eaa |
13011525451434 has 16 divisors (see below), whose sum is σ = 26182701523872. Its totient is φ = 4310566713648.
The previous prime is 13011525451391. The next prime is 13011525451439. The reversal of 13011525451434 is 43415452511031.
It is a junction number, because it is equal to n+sod(n) for n = 13011525451392 and 13011525451401.
It is not an unprimeable number, because it can be changed into a prime (13011525451439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6652108149 + ... + 6652110104.
It is an arithmetic number, because the mean of its divisors is an integer number (1636418845242).
Almost surely, 213011525451434 is an apocalyptic number.
13011525451434 is an abundant number, since it is smaller than the sum of its proper divisors (13171176072438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13011525451434 is a wasteful number, since it uses less digits than its factorization.
13011525451434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13304218421.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 13011525451434 its reverse (43415452511031), we get a palindrome (56426977962465).
The spelling of 13011525451434 in words is "thirteen trillion, eleven billion, five hundred twenty-five million, four hundred fifty-one thousand, four hundred thirty-four".
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