Base | Representation |
---|---|
bin | 11101100110111111101110… |
… | …111100100110110000001001 |
3 | 122002002012122022000010122121 |
4 | 131212333232330212300021 |
5 | 114032033423302442301 |
6 | 1140543402043251241 |
7 | 36300211240106422 |
oct | 3546775674466011 |
9 | 562065568003577 |
10 | 130223122312201 |
11 | 385473526a9856 |
12 | 12732144219b21 |
13 | 5787cac0b99a9 |
14 | 2422b930ca649 |
15 | 100c60793d3a1 |
hex | 766feef26c09 |
130223122312201 has 32 divisors (see below), whose sum is σ = 133260211814400. Its totient is φ = 127226630456640.
The previous prime is 130223122312187. The next prime is 130223122312331. The reversal of 130223122312201 is 102213221322031.
It is a cyclic number.
It is not a de Polignac number, because 130223122312201 - 215 = 130223122279433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130223122312001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22675101136 + ... + 22675106878.
It is an arithmetic number, because the mean of its divisors is an integer number (4164381619200).
Almost surely, 2130223122312201 is an apocalyptic number.
It is an amenable number.
130223122312201 is a deficient number, since it is larger than the sum of its proper divisors (3037089502199).
130223122312201 is a wasteful number, since it uses less digits than its factorization.
130223122312201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11869.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 130223122312201 its reverse (102213221322031), we get a palindrome (232436343634232).
The spelling of 130223122312201 in words is "one hundred thirty trillion, two hundred twenty-three billion, one hundred twenty-two million, three hundred twelve thousand, two hundred one".
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