130312441141042 has 16 divisors (see below), whose sum is σ = 201824508517632. Its totient is φ = 63038655095760.

The previous prime is 130312441141021. The next prime is 130312441141093. The reversal of 130312441141042 is 240141144213031.

130312441141042 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130312441141042² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a junction number, because it is equal to n+sod(n) for n = 130312441140995 and 130312441141013.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 262281613 + ... + 262777984.

It is an arithmetic number, because the mean of its divisors is an integer number (12614031782352).

Almost surely, 2^{130312441141042} is an apocalyptic number.

130312441141042 is a deficient number, since it is larger than the sum of its proper divisors (71512067376590).

130312441141042 is a wasteful number, since it uses less digits than its factorization.

130312441141042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 525063633.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 130312441141042 its reverse (240141144213031), we get a palindrome (370453585354073).

The spelling of 130312441141042 in words is "one hundred thirty trillion, three hundred twelve billion, four hundred forty-one million, one hundred forty-one thousand, forty-two".