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1304213242434 = 23730192976881
BaseRepresentation
bin10010111110101001001…
…010101100001001000010
311121200101212022100022020
4102332221022230021002
5132332012042224214
62435051452022310
7163140422435124
oct22765112541102
94550355270266
101304213242434
11463128413633
12190922461996
1395ca9c5b7bb
14471a4d6b214
1523dd3c6d4a9
hex12fa92ac242

1304213242434 has 16 divisors (see below), whose sum is σ = 2608463083680. Its totient is φ = 434731647680.

The previous prime is 1304213242429. The next prime is 1304213242457. The reversal of 1304213242434 is 4342423124031.

It is a super-3 number, since 3×13042132424343 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1304213242395 and 1304213242404.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1050327 + ... + 1926554.

It is an arithmetic number, because the mean of its divisors is an integer number (163028942730).

Almost surely, 21304213242434 is an apocalyptic number.

1304213242434 is an abundant number, since it is smaller than the sum of its proper divisors (1304249841246).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1304213242434 is a wasteful number, since it uses less digits than its factorization.

1304213242434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3049905.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 1304213242434 its reverse (4342423124031), we get a palindrome (5646636366465).

The spelling of 1304213242434 in words is "one trillion, three hundred four billion, two hundred thirteen million, two hundred forty-two thousand, four hundred thirty-four".

Divisors: 1 2 3 6 73019 146038 219057 438114 2976881 5953762 8930643 17861286 217368873739 434737747478 652106621217 1304213242434